Pyranose ring structure of glucose is due to hemiacetal formation between :a.) ${C_1}$ and ${C_5}$b.) ${C_1}$ and ${C_4}$c.) ${C_1}$ and ${C_3}$d.) ${C_2}$ and ${C_4}$
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A very common carbohydrate is d-glucose. It is aldohexose. Construct and draw a model of d-glucose, both straight and ring form. For the straight-chain draw its enantiomer. Explain the difference between the
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